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Plate Count Anomaly
Cautions
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As with most of the experiments in this course, you will be handling a variety of undomesticated organisms of unknown identity or pathogenicity. Handle all cultures with respect and using standard microbiological procedures. |
Introduction |
Since the early days of microbiology, it has been known that
cell counts of environmental samples obtained by cultivation (plate
counts or MPN) are much lower, by many orders of magnitude, than
direct microscopic cell counts. In this lab, the usual ratio is
about 10^-6 (i.e. one cell in a million seen grows up as
a colony), ranging from 10^-2 (1%) to <10^-8. Some of this
discrepency is attributable to differing requirements of organisms, e.g. aerobic plate counts on rich media will miss all obligate
anaerobes and autotrophs. In other cases, organisms are known
to enter a noncultivatable resting state, and many organisms rely
on each other for any of a variety of reasons and cannot be cultivated
in isolation. Imagine mixing all of the nutritional requirements
of a rabbit (carrots, water, air) in a huge fermentor, innoculating
with a big chunk of forest, and hoping to culture rabbits! In
any case, it is clear that what is readily cultivable is a miniscule
fraction of what's in a sample & the organisms that do grow
are almost by definition unlikely to represent the population
as a whole. |
Materials |
- pond water (from your Winogradsky column)
- Petrov-Hauser counters
- cover slips
- Phase-contrast microscope
- P20, P200 pipet guns and tips
- 0.1 ml sterile water blanks
- hockey sticks, EtOH
- LB plates
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Observations |
Calculate the concentration of observable cells in the pond
water based on the volume of water counted and the total cell
count. The dimensions of each of the small grid squares in the
Petrov-Hauser counter is 50um x 50um by 20um deep, or 5 x 10^-8
ml. So, take the average number of cells observed per small grid square (it's OK if this is less than 1), divided by 5 x 10^8 - the result is the number of cells obsvered per ml.
Also calculate the number of colony-forming-units (cultivable cells) per ml in the pondwater. This is just the number of colonies on a plate divided by the volume plated (in ml) - for example, 125 colonies from 0.01ml = 12500 cfu/ml.
Now calculate the fraction of observable cells that yielded colonies
under these cultivation conditions (colonies per ml divided by
cells per ml X 100%). Typical results are on the order of 0.0001%, ranging from 0 (no colonies) up to sometimes as high as 5%. |
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| Last updated
April 03, 2009
by James W Brown |